C实现枚举进程

2007-05-06 / Windows C/C++

/*
*  文件名：EnumProcess.c

*  用途：枚举进程
*  编程环境：WinXP SP2+CL 8.0
*  完成日期： 2006.2   Ver 0.01

*  作者： 88250

*  联系方式： E-mail: [email protected]  QQ:845765

*/

#include <stdio.h>

#include <windows.h>

#include <psapi.h>

#pragma comment(lib, "psapi.lib")

int main(void)

{

    DWORD processid[1024], pBytesReturned[1024], processSum, i;

    HANDLE hProcess;

    HMODULE hModule;

    char path[MAX_PATH] = "", temp[256];

    printf("ShowProcessPath with [Process Status API] ");

    EnumProcesses(processid, sizeof(processid), pBytesReturned);

    processSum = *pBytesReturned / sizeof(DWORD);

    for (i = 0; i < processSum; i++){

        hProcess = OpenProcess(PROCESS_QUERY_INFORMATION | PROCESS_VM_READ, FALSE, processid[i]);

        if (hProcess){

            EnumProcessModules(hProcess, &hModule, sizeof(hModule), pBytesReturned);

            GetModuleFileNameEx(hProcess, hModule, path, sizeof(path));

            GetShortPathName(path, path, 256);

            itoa(processid[i], temp, 10);

            printf("%s --- %s ", path, temp);

        }else{

            printf("Failed!!! ");        // 权限不够，不能访问有的进程

        }

    }

    CloseHandle(hProcess);

    CloseHandle(hModule);

    itoa(processSum, temp, 10);

    printf(" Process Count:%s ", temp);

    return 0;

}